What offspring will result from the mating of an Xg(a+) man and an Xg(a-) woman?

The mating of an Xg(a+) man and an Xg(a-) woman results in specific genotypes and phenotypes for their offspring based on X-linked inheritance. The man carries the Xg(a+) allele on his X chromosome, while the woman carries the Xg(a-) allele.

Males receive their X chromosome from their mother and their Y chromosome from their father. Therefore, the sons of this pairing will inherit the Y chromosome from their father and the X chromosome from their mother, which carries the Xg(a-) allele. Consequently, all sons will be Xg(a-).

Daughters, on the other hand, will inherit one X chromosome from each parent. Therefore, they will inherit the Xg(a+) allele from their father and the Xg(a-) allele from their mother. This results in all daughters being Xg(a+), as they possess one Xg(a+) allele.

In summary, the mating of an Xg(a+) man and an Xg(a-) woman will produce Xg(a-) sons and Xg(a+) daughters, aligning well with their genetic contributions.